The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
Answer:
m would be 1
Step-by-step explanation:
5^3 is 125 so it would be 1. I am pretty sure. Sorry if Im wrong!
Answer:
(5x+20)+(4x-11)=180(linear pair)
9x+9=180
9x=180-9
9x=171
x=171/9
x=19
now,
(2y+19)+(5x+20)=180(co-interior angle)
2y+19+5×19+20=180
2y+134=180
2y=180
y=180/2
y=90
To find the mid point add both X coordinates together and divide by 2 and then do the same with the y coordinates.
X coordinate: 4 + -6 = 4-6 = -2 / 2 = -1
Y coordinate: -2 + 3 = 1 / 2 = 1/2
Midpoint: ( -1, 1/2)
No, the answer is 3/8 because if 3/4 of the cars are Sudan's, and half of that three quarters are white, you need to divide three quarters into two to get the answer. I did this question by using the equivalent fraction 6/8 and dividing both numbers into two.
