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weqwewe [10]
3 years ago
13

Please Help!!!!!!!!

Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

  • rotation 90° CCW
  • translation 2 units upward

Step-by-step explanation:

It can help to draw a diagram.

In the attached diagram, the red triangle (RST) is the original, the purple one (ABC) is after rotation CCW by 90°, and the blue one (R'S'T') is after that is translated upward 2 units. R'S'T' is the final position.

Since RS and R'S' are oriented 90° with respect to each other, clearly a CCW rotation of that amount is required. The trick is to figure out which direction the translation occurs.

The translation can be done before or after the rotation. If done before, it needs to be 2 units to the right (not a choice). If done after, it can be 2 units up, as in this drawing.

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Rewrite in simplest terms: (-8x + 5) - (x – 7)​
Ilia_Sergeevich [38]

Answer:

-9x+12

Step-by-step explanation:

(-8x + 5) - (x – 7)​

Distribute the minus sign

(-8x + 5) - x + 7

Combine like terms

(-8x -x+ 5+7) ​

-9x +12

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3 years ago
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Rex's puppy is 5 years younger than his other dog. If the other dog is x years old, what is an expression for the puppy's age?
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The other dog's age is "x". Rex's puppy is 5 years less than "x". SO...
x-5.

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Maddi has a bin shaped like a right prism. She knows that the area of the base of the bin is 14 in² and the volume of the bin is
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2 years ago
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A kite is flying 20 ft off the ground. Its line is pulled taut and casts a 15 ft - shadow. Find the length of the line. If neces
Kryger [21]

Answer:

The answer to your question is 25 ft

Step-by-step explanation:

Data

height = 20 ft

leg = 15 ft

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To solve this problem use the Pythagorean theorem.

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leg = long leg = a

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- Substitution

         c² = (20)² + (15)²

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6 0
3 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
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