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creativ13 [48]
3 years ago
8

One Year, the price of wheat was $8.87 per bushel. The next year, the price was $9.60. Round the price per bushel of wheat for e

ach year to the nearest tenth of a dollar?
Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
Next year the price is going to be 10.23
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What is the slope and the y intercept of the equation -5x+3y=15
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Answer: the slope is 5/3 and the y-intercept is (0,5)
6 0
3 years ago
Describe the type of correlation indicated by each correlation coefficient r=0.875
Alenkinab [10]

Answer:

A strong correlation

Step-by-step explanation:

The closer the correlation coefficient is to the number 1 the stronger the correlation is.

5 0
3 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
1. Contaminated water is subjected to a cleaning process. The concentration of the
Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0
3 years ago
Jack puts the letters of the word BUILDING on pieces of paper and puts the pieces in a bag. He draws two letters without looking
Zepler [3.9K]

there are 8 letters

2/8 to get i on the first draw

1/7 to get i on the second draw (no replacement)

2/8 * 1/7 = 2/56

1/28


The probability is 1/28

5 0
2 years ago
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