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2 years ago

12

the area A of a sector circle is given by A= ... idk how to write that so look at the image please lol

2 answers:

Pavel [41]2 years ago

5 0

A=πr^2s/360 multiply both sides by 360

360A=sπr^2 divide both sides by πr^2

s=360A/(πr^2)

natima [27]2 years ago

5 0

It's D
but the problem is wrong
at the end shoud have been
Solve the equation for S to find the angle measure given the radius and the area of the SECTOR not the circle
if they give you the radius of the circle then...
the area is redundant since circle area is pi*r^2

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serg [7]

Answer:

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Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

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Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

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2 years ago