A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one hour is:

What is the order of the events for the water cycle on a typical warm day?

Rudik [331]

B precipitation,condensation,precipitation

6 0

3 years ago

The laws of refraction and reflection are the same for sound and for light.? The speed of sound is 340 m/s in air and 1510 m/s i

maria [59]

Answer::θ = 67.4242°

Explanation:

3 0

3 years ago

A group of a few thousand stars that are loosely held together by gravity is called a

zalisa [80]

Would it be an open cluster

8 0

4 years ago

A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas

Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut $M_{1}$ = 60.0 kg

Mass of male astronaut $M_{2}$ = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = $\frac{G*M_{1}*M_{2}}{S^{2} }$

G = 6.67*10^-11 $\frac{m^{3} }{kg*s^{2} }$

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/ $M_{1}$ = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/ $M_{2}$ = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

$a_{average} = \frac{a_{1}+a_{2}}{2}$ = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2) where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0

3 years ago

Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen

dsp73

Answer:

The spacing between the slits is $d = 0.00145m$

Explanation:

From the question we are told that

The wavelength of the light is $\lambda = 406.192nm = 406.192*10^{-9} m$

The distance of the slit from the screen is $D = 5.937 \ m$

The number of bright fringe is $n = 24$

The length the fringes span is $L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m$

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

$\beta = \frac{\lambda D}{d}$

Where d is the distance between the slits

$\beta$ is the fringe width which can also be evaluated as

$\beta = \frac{L}{n}$

Substituting values

$\beta = \frac{0.0398}{24}$

$\beta = 1.660 *10^{-3}$

Making d the subject of formula in the above equation

$d = \frac{\lambda D}{\beta }$

Substituting values

$d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}$

$d = 0.00145m$

4 0

4 years ago