Answer:
$6.68
Explanation:
The current running through the device would be its outlet voltage divided by the resistance:
I = U/R = 115 / 11.4 = 10.09 A
The power generated by this device is the product of its current and voltage
P = IU = 10.09 * 115 = 1160 W or 1.16 kW
If running this device for 36 hours then the total energy it would consume is
E = Pt = 1.16 * 36 = 41.76 kWh
Therefore the total cost of electrical energy is
C = Ec = 41.76*0.16 = $6.68
Answer:
1a) 857143 m
1b) 414 m
2a)
2b)
3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.
Explanation:
Question 1a)
Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.
[ λ = v / f ] wavelength = <u>v</u>elocity of the wave / <u>f</u>requency of the wave in Hz.
Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.
Anything to the negative power is reciprocated. i.e ms^-1 = m/s.
The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m
Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1
Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz
The wavelength is found using the same
formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m
Question 2a)
Question 2b)
Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.
Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =
Question 4)
<span>The jump from 1966 to 16347 is the largest one or simply we can say it is hard to lose the 3rd electron.Whereas, it is relatively easy to lose the first two electrons.
So there will be only 2 electrons in the outer most shell.
According to the information mentioned above we can conclude the </span><span>unknown element likely belongs to the second group.
</span><span>I2 = 1752 kj/mol</span>
I know that 4. Is wave 2 and 5. Is wave 3.