In which of the following sets do all species have the same number of electrons
2 answers:
Answer:
Option a
Explanation:
a)
Atomic number of I = 53
No. of electrons = atomic number + no. of negative charge
= 53 + 1 = 54
Xe
Atomic number of Xe = 54
In a neutral atom, no. of electron is equal to no. of protons.
So. no. of electron in Xe = 54
a)
Atomic number of I = 56
No. of electrons = atomic number - no. of positive charge
= 56 - 2 = 54
All the species in the set a have 54 electrons.
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Answer:
- Take 3.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.
- Take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL
Explanation:
Hello,
In this case, given that the dilutions are preparedfrom 3.0-M and 6.0-M hydrochloric acid, we must proceed as follows:
- 3.0-M stock: when using this stock, the aliquot you must take is computed as shown below:
It means that you must take 23.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.
- 6.0-M stock: when using this stock, the aliquot you must take is computed as shown below:
It means that you must take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL.
Regards.