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Ugo [173]
3 years ago
12

The water cycle is also known as the _______ cycle?

Chemistry
2 answers:
quester [9]3 years ago
8 0

Answer:

Hydrological Cycle :)

Explanation:

valina [46]3 years ago
4 0

Answer:

hydrological cycle

Explanation:

water cycle is also known as hydrological vycle

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Determine the number of ions produced in the dissociation of the compound listed. AlF3
scoray [572]
Answer is: the number of ions produced in the dissociation of aluminium fluoride is 4.
<span>
Chemical dissociation of aluminium fluoride in water:
AlF</span>₃(aq) → Al³⁺(aq) + 3F⁻(aq).<span>
There are four ions, one aluminium cation and three fluoride anions.
Aluminium has oxidation +3, because it lost three electrons, to have electron configuration as noble gas neon and fluorine has oxidation -1, because it gain one electron to </span>have electron configuration as noble gas neon.
6 0
3 years ago
Why Is Any Chemical Reaction always Balanced? Give reasons and Explain the Easiest way to solve the Balancing Problems in Chemic
erastova [34]

Answer:

The chemical equation needs to be balanced so that it follows the law of conservation of mass. A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

8 0
3 years ago
A 0.1 mm sample of human blood has approximately 6000 red blood cells. An adult typically has 5.0 L of blood. How many red blood
olga55 [171]

 3.0 × 10¹¹ RBC's    (or)      3E11 RBC's


Solution:

Step 1: Convert mm³ into L;


As,


                                            1 mm³  =  1.0 × 10⁻⁶ Liters


So,


                                         0.1 mm³  =  X  Liters


Solving for X,


                       X  =  (0.1 mm³ × 1.0 × 10⁻⁶ Liters) ÷ 1 mm³


                       X  =  1.0 × 10⁻⁷ Liters


Step 2: Calculate No. of RBC's in 5 Liter Blood:


As given


                        1.0 × 10⁻⁷ Liters Blood contains  =  6000 RBC's


So,


                         5.0 Liters of Blood will contain  =  X  RBC's


Solving for X,


                      X  =  (5.0 Liters × 6000 RBC's) ÷ 1.0 × 10⁻⁷ Liters


                      X  =  3.0 × 10¹¹ RBC's


Or,


                     X  =  3E11 RBC's



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