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Zarrin [17]
3 years ago
11

PLEASE ANSWERRRRRRRRR

Chemistry
1 answer:
ira [324]3 years ago
3 0

Answer:

C. how the size of a magnet affects the strength of its magnetic pull on objects.

Explanation:

"Magnetic force" is <em>inversely proportional to distance squared. </em>This is also related to the size of a magnet. The bigger the size, the bigger the domain it occupies and the stronger the magnetic field. However, this is not often the case and it largely depends on the types of magnets.

In the situation above, Jazelle wanted to determine how her five different-sized magnet affect the strength of their magnetic pull on the paper clips. In order to do this, she tried to<em> measure the distance</em>. The<em> closer the distance</em>, the <em>higher the magnetic field</em> and the stronger the strength. The farther the distance, the<em> lower the magnetic field</em> and the <em>weaker the strength.</em>

So, this explains the answer.

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For the reaction Fe3O4(s) + 4H2(g) --&gt; 3Fe(s) + 4H2O(g)
mojhsa [17]

Answer : The value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = 151.2 kJ = 151200 J

\Delta S^o = standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(151200J)-(328.0K\times 169.4J/K)

\Delta G^o=95636.8J=95.6kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

95636.8J=-(8.314J/K.mol)\times (328.0K)\times \ln k

k=1.70\times 10^{15}

Therefore, the value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

3 0
3 years ago
How many grams of Cl2 are consumed to produce 12.0 g of KCl?
Alla [95]

The reaction is:

Cl2 + 2 KBr --> 2 KCl + Br2

Moles of KCl is

n = m /M = 12 /74 = 0.16 mol

As, twice the moles of KCl is producing from 1 mol of chlorine

mole of Cl2 = 0.16 /2 = 0.08 mol

Mass of Cl2

m /70 = 0.08 = 5.6 g

Hence, 5.6 g mol Cl2 consumed to produce KCl

7 0
3 years ago
Which is a substance that is made up of only one type of atom?
deff fn [24]
The answer is element
5 0
3 years ago
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Otrada [13]

Answer:

The answer is D) White Light!

7 0
3 years ago
Sodium metal is added to a solution of magnesium chloride. Will a reaction occur? If so, what reaction will take place?
Black_prince [1.1K]
Yes, calcium chloride forms.
4 0
3 years ago
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