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Mariana [72]
3 years ago
13

Which of the following are dipole-dipole interactions that occur only between molecules containing N-H, O-H or F-H bonds?

Chemistry
2 answers:
Lelu [443]3 years ago
8 0

Answer:

Hydrogen bonding

Explanation:

Hydrogen bonding is a type of dipole dipole interaction. It exist between H atom bonded to electronegative atom; O, N, F and other O, N, F of another molecule.

Some of the examples of compounds having hydrogen bonding are:

NH_3,\ H_2O,\ HF,\ CH_3OH,\ etc.

Hydrogen bonding exists because of development of dipole dipole interaction between H and electronegative atom.

As H is less electronegative as compared to O, N and F. So partial positive charge develop on H and partial negative chagre develop develop on the attached electronegative atom. Because of development of partial positive and partial negative charge, dipole dipole interaction occurs which leads to the development of hydrogen bonding.

ivolga24 [154]3 years ago
5 0

Answer:

Hydrogen bonding

Explanation:

Hydrogen bonds are special dipole-dipole attraction between polar molecules in which a hydrogen molecule atom is directly joined to a highly electronegative atom.

This type of bond is an intermolecular bond caused by an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom(O or N or F) of a neighbouring molecule.

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Which of the following would be considered an Exothermic Reaction?*
Digiron [165]

Answer:

Burning wood

Explanation:

the fire releases heat into the air from the burning wood

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2 years ago
What happens if the same zero error occurs in every reading
nadya68 [22]

Zero error occur in every reading means that the measuring instrument needs to recalibrated and adjusted.

<h3>What is Zero error?</h3>

This error occurs when a measuring instrument reflects a digit which isn't zero despite the real value being zero.

When this occurs, only the zero screw on the device should be adjusted so as to correct this technical error. This is why recalibration should be the most appropriate solution.

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3 0
1 year ago
What is the percent cr, by mass, in the steel sample? express your answer numerically as a percentage?
djverab [1.8K]
Given:3.40g sample of the steel used to produce 250.0 mLSolution containing Cr2O72−

Assuming all the Cr is contained in the BaCrO4 at the end. 
(0.145 g BaCrO4) / (253.3216 g BaCrO4/mol) x (250.0 mL / 10.0 mL) x (1 mol Cr / 1 mol BaCrO4) x (51.99616 g Cr/mol / (3.40 g) = 0.219 = 21.9% Cr
8 0
3 years ago
Read 2 more answers
Is there a way to dissolve more sugar into a solution that it should hold at that temperature? Explain how this is done and what
Darya [45]

The answer is: supersaturated solution.

A supersaturated solution contains more of the dissolved substance than could be dissolved by the solvent under normal circumstances.

A way to dissolve more sugar into a solution is heating a solution.

The more heat is added to a system, the more soluble a substance (in this example sugar) becomes.

The solution will become supersaturated if this solution is suddenly cooled at a rate faster than the rate of precipitation.

6 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
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