Given:
The equation is

To find:
The number of roots and discriminant of the given equation.
Solution:
We have,

The highest degree of given equation is 2. So, the number of roots is also 2.
It can be written as

Here,
.
Discriminant of the given equation is





Since discriminant is
, which is greater than 0, therefore, the given equation has two distinct real roots.
As far as the old dimensions of the photo are concerned,
Width of the photo = 3"
Length of the photo = 5"
New length of the photo = 7 inches
Let us assume the new width of the photo = x inches
Then
3/5 = x/7
5x = 7 * 3
5x = 21
x = 21/5
= 4.20 inches
So the correct option among all the options that are given in the question is the first option. I hope that the answer has come to your help.
Answer:
C(t)=5000 -10t
Step-by-step explanation:
There are many examples in the real world of relationships that are functions.
For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.
If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

Where:
C (t): Amount of water in the tank as a function of time
: Initial amount of water in the tank at time t = 0
a: amount of water lost per hour
t: time in hours
Then the equation is:
The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.
Its domain is the set of all positive real numbers t between [0,500]
Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty
Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres
Answer:
The cost of each pair of shoes before the discount=$67.65
Step-by-step explanation:
Step 1
Use the expression below to determine original cost of the 2 pairs of shoes as follows;
A=O-R
where;
A=total bill after discount
O=original cost of 2 pairs of shoe
R=discount amount
In our case;
A=$110.50
O=unknown=x
R=15% of O=(15/100)×x=0.15 x
replacing;
115=x-0.15 x
115=0.85 x
x=115/0.85
x=135.294
Original cost of the 2 pairs of shoes=$135.294
Original cost of a pair of shoes=135.294/2=$67.65
The cost of each pair of shoes before the discount=$67.65