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lutik1710 [3]
2 years ago
11

6 Factor the expression. 4z- 28

Mathematics
1 answer:
bulgar [2K]2 years ago
6 0

Answer:

Simplifying

4z = 28

Solving

4z = 28

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Divide each side by '4'.

z = 7

Simplifying

z = 7

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13.7142857143

Step-by-step explanation:

so just 13

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HELPPPPP ASAP!!!! Thx!! and NOOO FILESSSS!!
tiny-mole [99]

Answer:

x=32°

Step-by-step explanation:

The law of sines is a property of all triangles that relates the sides and angles of a triangle. This property states the following:

\frac{sin(a)}{A}=\frac{sin(b)}{B}=\frac{sin(c)}{C}

Where side (A) is the side opposite angle (<a), side (B) is the side opposite angle (<b), and side (C) is the property opposite angle (<c).

Substitute each of the sides and respective angles into the formula, and solve for the unknown angle (<x). Please note that a triangle with two congruent sides (referred to as an isosceles triangle) has a property called the base angles theorem. This states that the angles opposite the congruent sides in an isosceles triangle are congruent. Therefore, there can be two (<x)'s in this triangle.

\frac{sin(a)}{A}=\frac{sin(b)}{B}=\frac{sin(c)}{C}

\frac{sin(x)}{10}=\frac{sin(116)}{17}=\frac{sin(x)}{10}

One can shorten the equation so it only holds the parts that will play a role in solving this equation,

\frac{sin(x)}{10}=\frac{sin(116)}{17}

Now take the cross product in this equation to simplify it further,

\frac{sin(x)}{10}=\frac{sin(116)}{17}

17(sin(x))=10(sin(116))

Inverse operations, solve this equation for (x),

17(sin(x))=10(sin(116))

sin(x)=\frac{10(sin(116))}{17}

x=sin^-^1(\frac{10(sin(116))}{17})

x=31.91782...

x\approx32

4 0
3 years ago
Read 2 more answers
I need help please help me thanks please
Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})

\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright  y = 4x+(-1)\blacktriangleleft

4 0
2 years ago
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