The lifeguard of the beach resort is on his post which is 4 m high. A boy in the pool is 9 meters away from him. Find the angle of depression from the lifeguard to the boy.

$\large\underline{ \mathbb{ANSWER \: \& \: SOLUTION:}}$

$\large \tt{ tan \: x \: = \: \frac{opposite}{adjacent} }$

$\large \tt{tan \: x \: = \: \frac{4}{9}}$

$\large \tt{ \: \: \: \: \: \: \: \: x \: = \: tan ^{ - 1} \: (0.444)}$

$\large \tt {\: \: \: \: \: \: \: \: x \: = \: 23.96 ^{o} }$

$\:\:\:\:\:\:\:\: \large \boxed{\tt{\red{ x \: = \: 24 ^{o} }}}$

Therefore the angle of depression from the lifeguard to the boy is 24°.

8 0

2 years ago

Whattttt minion meme

AVprozaik [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which shows all the names that apply to the figure?

Sloan [31]

B. parallelogram , rhombus , and rectangle

6 0

3 years ago

Read 2 more answers

How many time does 16 go into 4

Artemon [7]

4 can go into 16 4 times

6 0

2 years ago

Read 2 more answers