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Tanya [424]
2 years ago
6

The term in a linear prediction rule that represents the intercept of a regression line is

Mathematics
1 answer:
kipiarov [429]2 years ago
7 0
 Linear Production is defined as a mathematical operation where future values of a discrete-<span>time signal are estimated as a </span>linear<span> function of previous samples.</span><span>
The term in a linear prediction rule that represents the intercept of a regression line is:
a= y intercept = regression constant
b = slope = regression coefficient</span>
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gogolik [260]
3,000.000 + 500.000 + 16.000 + 500 + 60 + 8 - Hope it helps!
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QUICK FOR 10 POINTS
Shtirlitz [24]

Answer:

8 pencils

Step-by-step explanation:

We can reverse everything that is happening in the problem like this!...

Jeremiah has 20 - 4 pencils = 16 than 2 reverse operation of multiplication which will be division then 16 ÷ 2 = 8

Check work? 8 more than 2 times equals 16 + 4 more that Jeremiah has equals 20 pencils

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Nathan needs some paint for his bedroom. He finds two cans of white paint, four cans of green paint and three cans of pink paint
horsena [70]

The probability of randomly selecting a can of pink paint is P = 1/3, so the correct option is A.

<h3>What is the chance that he will paint his bedroom pink?</h3>

Assuming that all the cans of paint have the same probability of being randomly selected, the probability that he will choose a pink can is equal to the quotient between the number of pink cans and the total number of cans.

There are 2 cans of white, 4 cans of green, and 3 cans of pink, so a total of 9 cans.

Then the probability is:

P = 3/9 = 1/3.

The correct option is A.

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4 0
2 years ago
Find the angle of elevation of a kite on a 50m<br> string flying 40m vertically above the ground.
Lera25 [3.4K]
Sin(x)=40/50
x= sin^-1(40/50)
x= 53.1301023542—>53.1 rounded to the nearest tenth
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6 0
2 years ago
An online poll has a question that appears on the screen, and you simply click buttons to vote "Yes, " "No, " "Not sure, " or "D
Nataly_w [17]

Complete  Question

An online poll has a question that appears on the screen, and you simply click buttons to vote "Yes, " "No, " "Not sure, " or "Don't care." On a particular day, the results of a question were tallied. In all, 636 said "Yes, " another 595 said "No, " and the remaining 93 indicated that they were not sure.

a)

What is the sample size for this poll?

b)

Compute the percent of responses in each of the possible response categories. (Round your answers to two decimal places.)

c)

Discuss the poll in terms of the population and sample framework that we have studied in this chapter.

i)

This random sample of responses collects the opinions of a random group of users across all users of the Internet.

ii)

This voluntary response sample collects only the opinions of those that visit this site every day.

iii)

This random sample of responses collects the opinions of a random group of users of the particular site.

iv)

This voluntary response sample collects only the opinions of those who visit this site and feel strongly enough to respond.

Answer:

a

   n  =  1324

b

  YES             y  = 48.03 \%

    NO             m  =44.94 \%

   NOT SURE  m  =7.02\%

c

The correct option is (iv)

Step-by-step explanation:

From the question we are told that

The voting options are "Yes, " "No, " "Not sure, " or "Don't care."

The number of people that said is Y =  636

The number of people that said No is N = 595

The number that indicated Not sure is S =  93

Generally the sample size is mathematically represented as

n  = Y  +  N  + S

=> n  =  636  +   595  + 93

=> n  =  1324

Generally the percentage of responses that was Yes is mathematically represented as

y  =  \frac{636}{ 1324}  * 100

=>     y  = 48.03 \%

Generally the percentage of responses that was No is mathematically represented as

m  =  \frac{595}{ 1324}  * 100

m  =44.94 \%

Generally the percentage of responses that was Not sure is mathematically represented as

s  =  \frac{93}{ 1324}  * 100

m  =7.02\%

This voluntary response sample collects only the opinions of those who visit this site and feel strongly enough to respond.

4 0
3 years ago
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