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3 years ago

The perimeter of triangle ABC is 36 cm. Its sides are proportional to the numbers 3, 4 and 5. Find the sides of the triangle.

Mathematics

1 answer:

DiKsa [7]3 years ago

5 0

Answer:

3x+4x+5x=36

12x=36

x=36/12

x=3

3x=3 into 3=9

4x=4 into 3=12

5x=5 into 3=15

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What is the LCM of 12 and 18

worty [1.4K]

Lcm is found by finding the factors and making a mega group with all the factors of both groups, excluding repeats from different groups so
12=2 times 2 times 3
18=2 times 3 times 3
megagroup=2 times 2 times 3 times 3=4 times 9=36
the LCM=36

5 0

3 years ago

Read 2 more answers

The ratio of the number of cookies in Jar A to the number of cookies in Jar B is 3:8. Half of the cookies in Jar A are transferr

motikmotik

The new ratio of the number of cookies in Jar A to the number of cookies in Jar B in the end is 5 : 19

<h3>How to find ratio</h3>

Ratio of jar A to jar B = 3 : 8

Jar B = 1/2 of A + B

= 1/2 × 3 + 8

= 3/2 + 8

= (3+16) /2

= 19/2

Jar A = 3 - 1/2

= (6-1) /2

= 5/2

New ratio of jar A to jar B = 5/2 : 19/2

= 5/2 ÷ 19/2

= 5/2 × 2/19

= 5/19

= 5 : 19

Learn more about ratio:

brainly.com/question/2784798

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2 years ago

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y <

levacccp [35]

<u>Solution-</u>

The given inequalities are,

$y < 2x-7,\\\\y\geq-\frac{1}{2}x+3$

As the former inequality is only '<' so it will be represented as dotted line, but in case of the later inequality there is '≥' so it will be represented as a solid line.

This happens because in only '<, >' the values must be either lesser or greater than y, they can't take the values of y, but in case of '≤, ≥' the values can be equal to y.

Taking origin (0, 0) and putting in the first inequality.

$\Rightarrow 0< 2(0)-7\\\\\Rightarrow 0\nless -7$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

Again taking origin (0, 0) and putting in the second inequality.

$\Rightarrow 0\geq-\frac{1}{2}0+3\\\\\Rightarrow 0\ngeqslant 3$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

The second attachment contains the feasible region.

In order to know whether the point (3, −7) is included in the solution area for the system or not, we must put it in both the equations, if it satisfies both then only it is within the solution area.

$\Rightarrow -7< 2(3)-7,\ -7\geq-\frac{1}{2}(3)+3\\\\\Rightarrow -7$