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4 years ago

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A stick 1 meter long casts a shadow 1.5 meters long. A building casts a shadow 17 meters long. How tall is the building (to 2 de

cimal places)

1 answer:

torisob [31]4 years ago

8 0

I’m not sure keep trying

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The ranger of the function x2+2x-8is allá

allsm [11]

Answer:

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

As the function is

$x^{2} +2x-8$

As we know that domain is the set of input values for which the function is defined.

Therefore,

$\mathrm{Domain\:of\:}\:x^2+2x-8\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

And range is defined as:

The set of the dependent variable for which the function is defined.

As

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(-1,\:-9\right)$

$f\left(x\right)\ge \:-9$

Therefore,

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Keywords: graph, domain, range

Learn more about domain and range from brainly.com/question/13856645

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8 0

3 years ago

Which would stop a plant from being able to grow?

Nikitich [7]

C: not getting enough sunlight

4 0

4 years ago

Read 2 more answers

Suppose the mean height of women age 20 years or older in a certain country is 62.7 inches. One hundred randomly selected women

zmey [24]

Answer: No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

Step-by-step explanation:

Since we have given that

$H_0:\mu =62.7\\\\H_a:\mu \neq 62.7$

Mean height = 61.5 inches

Standard deviation = 4.4 inches

n = 100

So, test statistic value would be

$z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{61.5-62.7}{\dfrac{4.4}{\sqrt{100}}}\\\\z=\dfrac{-1.2}{0.44}\\\\z=-2.727$

At 10% level of significance, in two tail test ,

z = 1.28

Since 1.28 > -2.727

So, we will accept the null hypothesis.

Hence, No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

7 0

4 years ago

What's the product of 42⁄3 and 111⁄4 ?

olga nikolaevna [1]

4 2/3 * 11 1 /4

change to improper fractions

4 2/3 =(3* 4+2)/3 = 14/3

11 1/4 = (4* 11+1)/ 4 =45/4

14/3 * 45/4 = 630/12

105/2

52 1/2

4 0

4 years ago

Read 2 more answers

Find the area of this shape

chubhunter [2.5K]

Personally the easiest way for me is to first find the area of the rectangle and take away the missing triangles. So assuming it’s a rectangle we get (4+5)(3+2) = 45. Ok now we find the area of the triangles. 0.5(4)(3) = 6. Now we subtract that twice from our 45.
45-6-6 = 33. The answer is 33

6 0

3 years ago

Read 2 more answers