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Dima020 [189]
3 years ago
15

What are the dimensions of the largest rectangular field that can be enclosed with 64m of wire?​

Mathematics
1 answer:
Natalka [10]3 years ago
7 0

Step-by-step explanation:

perimeter = 2*length + 2*width

area = length*width

perimeter = 64

Rectangular means all the corners have to be right angles.

If we say it can be a square, then...

perimeter = 4*side

64 / 4 = side

side = 16 meters

So the dimensions would be 16 m x 16 m

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Pythagorean theorem
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Answer:

b=20 yards

Step-by-step explanation:

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225+x^2=625

x^2=400

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What is the value of this expression? 42+3×5−(15−3×6)2 4 2 + 3 × 5 − ( 15 − 3 × 6 ) 2
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The solution is the B. 22
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3 years ago
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Answer:29

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Step-by-step explanation:

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2 years ago
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The mean or average speed of a mobile moving north is: <u>Vprom= 20.575 m/sec</u>

The average speed of a series of given speed values ​​is calculated by <u>summing</u> each of the <u>speeds</u> and then <u>dividing</u> by the number of speeds , as follows:

Speeds:

V1=18.5m/s

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V3=20.3m/s

V4=21.5m/s

 V avg =?

Average V = ( V1+V2+V3 +V4)/4

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Vavg = 20.575nm/sec

To consult visit: brainly.com/question/11100327

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I believe that triangle B and E are right triangles.
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3 years ago
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