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Mariana [72]
3 years ago
14

Let f be a continuous function on the closed interval [ − 2 , 5 ]. If f((-2)=-7 and f(5)=1, then the Intermediate Value Theorem

guarantees that
Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

The function has at least 1 zero within the interval [-2,5].

Step-by-step explanation:

The intermediate value theorem states that, for a function continuous in a certain interval [a,b], then the function takes any value between f(a) and f(b) at some point within that interval.

This theorem has an important consequence:

If a function f(x) is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:

f(a)>0\\f(b) (or viceversa)

Then the function f(x) has at least one zero within the interval [a,b].

We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval

[-2,5]

And we also know that the function changes sign at the extreme points of the interval:

f(-2)=-70

Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that

f(x')=0

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Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
What is the slope of a line perpendicular to y = -7/4x?
dexar [7]
A line is perpendiculat to another which has a slope of m if the perpendicular line has a slope of -1/m.
That means that if the product of slopes of two lines is -1, the two lines are perpendicular.

Here, y1=-7/4x, or m=-7/4
The perpendicular should have a slope of -1/m=-1/(-7/4)=4/7
6 0
3 years ago
Help please I needed!!!!
faust18 [17]

Answer:

Step-by-step explanation:

4. f(x) = √(x + 4)

f(5) = √(5+4) = √(9) = 3

5. g(x) = x^12 - x^5

  g(-1)=          (-1)^12 - (-1)^5

             1 - (-1) = 1 + 1 = 2

3 0
3 years ago
Need help on this ASAP
serg [7]

Answer:

so what to fo tell in brief

if u have time

3 0
3 years ago
What type of triangle is shown here?
Naddika [18.5K]
Equilateral because all sides are equal
5 0
2 years ago
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