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Andrews [41]
3 years ago
7

Consider the function p(c)=2^c+1 . What is p(3)?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

The answer to your question is:

Step-by-step explanation:

Data     I'm not sure if number 1 is a power of not, so I'll answer both cases.

1.- Number 1 is not a power

            p(c) = 2^c + 1

            p(3) = 2³ + 1

            p (3) = 8 + 1

            p(3) = 9

2.- Number 1 is a power

            p(c) = 2^c + 1

            p(3) = 2^3 + 1

            p(3) = 2^4

            p(3) = 16

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Emily had 75 buttons. She gave 15 to Jake. What percent of buttons did she give to Jake?
eduard

Answer:

20%

Since Emily gave 15 of her buttons out of 75, it's just 15/75 or 1/5 which is 20

Step-by-step explanation:

8 0
2 years ago
Express the system as AX = B; then solve using matrix inverses
Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]

\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B

Adj.A=Transpose of cofactor of Matrix A

Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2

2.

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

   A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]

\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4

7 0
3 years ago
What numbers does the square root of 125 fall between
attashe74 [19]
9 and 10

11 and 12

13 and 14

15 and 16

the square root of 125 is 11.18 so therefore it falls between 11 and 12
3 0
2 years ago
Read 2 more answers
Answer ASAP!
valentinak56 [21]

Answer:

A and D

Step-by-step explanation:

Since tangent is opposite/adjacent,

Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)

So, you set it up as an algebra problem

Tan40 = x/3.8

Multiply both sides by 3.8

3.8tan40 = x, Option A

And then, angle E is 50 degrees

So tan 50 = 3.8/x

Multiply both sides by x

tan50x = 3.8

Divide both sides by tan50

x= 3.8/tan50

So, A and D are both correct

3 0
2 years ago
Please answer I'm giving out a thanks, follow, and a brainliest.
Sveta_85 [38]

The mode of a set of numbers is the number that occurs the most.

The numbers in this set are as follows,

26, 17, 9, 12, 18, 21, 9, 14, 18, 23, 15, 7, 20, 18, 17, and 12

26 I

17 II

9 II

12 II

18 III

21 I

14 I

23 I

15 I

7 I

20 I

The number that appears the most is 18!

So the mode of the set of numbers is 18!



3 0
3 years ago
Read 2 more answers
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