The length of a rectangle is three times it's width. If the perimeter of the rectangle is 64, find its length and width
1 answer:
set up an equation for the perimeter
l = length w = width
2l + 2w = 64
set up another equation as you know the length is 3 times the width
w = 3l
subsitute w = 3l into the 2l + 2w = 64
2l + 2(3l) = 64
solve for l
2l + 6l = 64
8l = 64
<em><u>length</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em>
subsitute into w = 3l
w = 3(8)
<em><u>width</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em>
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