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BaLLatris [955]
3 years ago
10

Solve for x: 3|x - 3| + 2 = 14

Mathematics
2 answers:
Xelga [282]3 years ago
7 0
Two solutions,
x=7
x=-1
So, D would be your answer.
PilotLPTM [1.2K]3 years ago
3 0
1 Subtract 22 from both sides
3|x-3|=14-23∣x−3∣=14−2

2 Simplify 14-214−2 to 1212
3|x-3|=123∣x−3∣=12

3 Divide both sides by 33
|x-3|=\frac{12}{3}∣x−3∣=
​3
​
​12
​​

4 Simplify \frac{12}{3}
​3
​
​12
​​ to 44
|x-3|=4∣x−3∣=4

5 Break down the problem into these 2 equations
x-3=4x−3=4
-(x-3)=4−(x−3)=4

6 Solve the 1st equation: x-3=4x−3=4How?
x=7x=7

7 Solve the 2nd equation: -(x-3)=4−(x−3)=4How?
x=-1x=−1

8 Collect all solutions
x=-1,7x=−1,7
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Find the measure of each angle indicated. Round to the nearest tenth.
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4 0
2 years ago
It is desired to determine whether there is less variability in the silver plating done by Company 1 than in that done by Compan
uysha [10]

Answer:

The conclusion is True

Step-by-step explanation:

Solution:

- The standard deviation of company s1 = 0.035

- The standard deviation of company s2 = 0.062

- Null Hypothesis : s1^2 = s2^2

- Alternate hypothesis : s1^2 < s2^2

- Criteria to reject Null: M > M_a ( 12 - 1 , 12 - 1 )

- From Tables,  M > 2.82

- M - statistics value M = s2^2 / s1^2

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8 0
4 years ago
HELP PLEASE! Can you please explain so I can understand how it was completed?
nlexa [21]

Answer:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

Step-by-step explanation:

Hello!

We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.

We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:

  • The radial coordinate which is often denoted by r.
  • The angular coordinate by θ.

So we need to find r and θ. So we know that:

r=\sqrt{x^{2}+y^{2}}       (1)

x = rcos(θ)                                   (2)

x = rsin(θ)                                    (3)

From the statement we know that (x, y) = (3, -3).

Using the equation (1) we find that:

r=\sqrt{x^{2}+y^{2}}=\sqrt{3^{2}+(-3)^{2}} = 3\sqrt{2}

Using the equations (2) and (3) we find that:

3 = rcos(θ)

-3 = rsin(θ)

Solving the system of equations:

θ= -45

Then:

r = 3\sqrt{2}[/tex]

θ= -45 or 315

Notice that  there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.

So, the solution is:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

4 0
3 years ago
A landscape plan includes a rectangular flower bed that is surrounded the wood planks. In the drawing, the rectangular flower be
True [87]

Step-by-step explanation:

we have

length =8in

breadth =6in

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new

length=8×24=192in

breadth =6×24=144in

(b) What is the perimeter of the actual flower bed ? Show your work.

<em>answer:the perimeter of the</em><em> </em><em>actual flower bed</em><em> =2(l+b)</em>

<em> =2(l+b)=2(192+144)=672</em><em>in</em>

(a) What is the perimeter of the drawing? Show your work

<em>answer</em><em> </em><em>:</em><em> </em><em>the perimeter of the </em><em>drawing</em>

<em>=</em><em>2</em><em>(</em><em>8</em><em>+</em><em>6</em><em>)</em><em>=</em><em>9</em><em>6</em><em>in</em>

<em>(c) What is the effect on the perimeter of the flower bed with the dimensions are multiplied by 24? Show your work</em>

<em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>flower </em><em>bed</em><em> </em><em>/</em><em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>d</em><em>r</em><em>a</em><em>w</em><em>i</em><em>n</em><em>g</em>

<em>=</em><em>9</em><em>6</em><em>/</em><em>6</em><em>7</em><em>2</em><em>=</em><em>1</em><em>/</em><em>7</em>

<h3><em>perimeter</em><em> </em><em>of</em><em> </em><em>drawing</em><em> </em><em>is</em><em> </em><em>increased</em><em> </em><em>by</em><em> </em><em>7</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>of</em><em> </em><em>perimeter</em><em> </em><em>of</em><em> </em><em>flower</em><em> </em><em>bed</em></h3>

3 0
3 years ago
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