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rodikova [14]
2 years ago
14

Using the quadratic formula to solve 4x^2 – 3x + 9 = 2x + 1, what are the values of x?

Mathematics
1 answer:
katrin [286]2 years ago
3 0
C but i could be wrong lol very wrong.
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Give a number that is not in the domain of <br><br> f(x) = √3x-6
Harman [31]
Any number that is less than 2 will work. It is impossible to find the square root of a negative number (you can only get imaginary number) since anything square is a positive number.
PS. If you are confused by the answer, just ask me.
5 0
2 years ago
Which statements are true?
Rina8888 [55]

Answer:

The first one and the last one are true (Since −6 is 6 units to the left of 0, |−6|=6 and −6 is closer to zero on the number line than −7, so |−6|<|−7|.)

Step-by-step explanation:

Absolute value is the distance to zero, and it is always positive. That means the positive and negative versions of a number have the same absolute value. That means the first one is true, and the second and third ones are false. For the last one, -6 is closer to zero, so that means it would be true (The absolute value of -6 is 6, and the absolute value of -7 is 7).

4 0
3 years ago
Giving out brainiest to the people who help me answer these three questions!!!
professor190 [17]

Answer:

Same question Four times no answer

3 0
2 years ago
The equation for the cost in dollars of producing automobile tires is c = 0.000015x2 - 0.03x + 35, where x is the number of tire
statuscvo [17]
The cost function is
c = 0.000015x² - 0.03x + 35
where x = number of tires.

To find the value of x that minimizes cost, the derivative of c with respect to x should be zero. Therefore
0.000015*2x - 0.03 = 0
0.00003x = 0.03
x = 1000

Note:
The second derivative of c with respect to x is positive (= 0.00003), so the value for x will yield the minimum value.

The minimum cost is
Cmin = 0.000015*1000² - 0.03*1000 + 35
          = 20

Answer:
Number of tires = 1000
Minimum cost = 20
3 0
3 years ago
Subject Algebra 1
Mashutka [201]

Answer:

10x^{2}-34

Step-by-step explanation:

Because we are told equivalent expressions for y and z we can plug those in to 2(y+z).

2((3x^{2}+x^{2}-5)+(x^{2}-12))

Then simplify by combining like terms of the expressions. Values ending in x^2 can be combined with each other.

2(5x^{2}-17)

Now we can distribute the 2 by multiplying each value in the parentheses by 2.

10x^{2}-34

6 0
3 years ago
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