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3 years ago

Identify the initial amount a and the growth factor b in the exponential function. F (t)=1.4^t

1 answer:

7 0

Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4

f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4

Hope his helps!!!!!!!

Ps: Please mark brainliest!!!! I am only a few away from ranking up, it would help a lot, and I will make a shoutout for you!!

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6 more than a number

jolli1 [7]

Answer:

Step-by-step explanation:

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3 years ago

The following data represent the monthly rent of 10 two-bedroom condos in Oviedo, Florida.

romanna [79]

Answer:

20th percentile.

Step-by-step explanation:

Concept of a percentile:

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Determine the percentile of the condo with a monthly rent of $1,150

There are 10 values.

8 are higher than $1,150.

2 are $1,150 or lower.

2/10 = 0.2 = 20%

So the condo with a monthly rent of $1,150 is in the 20th percentile.

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4 years ago

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Molodets [167]

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3 years ago

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu

Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

Traditional Accelerated Total

Math-pathway Math-pathway

Female 1244 116 1360

Male 1054 54 1108

Total 2298 170 2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events A and B are independent then:

$P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)$

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

$P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}$

If the two events are independent then:

P (F|A) = P(F)

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0

3 years ago

Tbh this question confusing the **** outta me

trapecia [35]

Answer:

$8^6$

Step-by-step explanation:

Powers are defined as the number of times you multiply a number by itself. For example, 2 to the 3rd power is 2 multiplied by itself 3 times. 2 * 2 * 2 = 8. You also know that if you multiply two powers of the same base, you add the exponent, and if you raise a power to a different power, you multiply the exponents.

e.g:

$2^2\cdot2^2=2^{2+2}=2^4\\(2^2)^3=2^{2\cdot3}=2^6$

Now, we are asking to use grouping to write 2 to the power 18 as a power of 8. We know 2 to the power 8 is 2 to the power 3, so we have the following equation:

$2^{18}=(2^3)^x$

We know this is now 2 to the power 3x = 2 the power 18, and therefore x = 6, because 3 times 6 is equal to 18. Now, we can just simplify 2 to the third as 8 and we now have:

$8^6$

4 0

2 years ago