The expected value of the game is the mean value of the game
The expected value of the game is $1
<h3>How to determine the expected value?</h3>
There are 13 spades in a deck of card of 52
So, the probability of selecting a spade is:
P(Spade) = 13/52
Simplify
P(Spade) = 1/4
Winning = $7
The probability of not selecting a spade is:
P(Not spade) = 1 - 1/4
Simplify
P(Not spade) = 3/4
Lose = $1
The expected value of the game is:
This gives
Simplify
Evaluate
Hence, the expected value of the game is $1
Read more about expected values at:
brainly.com/question/15858152
Answer:
x+5^3
Step-by-step explanation:
Let x be the number
cubed is raised to the third power
x+5^3
What you do is divide 19.5 by 3 which is 6.5. So every bag would weight 6.5 lbs
Answer:
1). Increases
2). Slope = 4
3). Slope = -1
4). y = 4 when x = 5
Step-by-step explanation:
1). Initially, as x increases, y also increases. (Linear growth has been shown in the graph initially).
2). Afterward, the slope of the graph of the function is equal to 4 for all x between x = 3 and x = 5.
[Slope of the line passing through two points (3, 0) and (5, 4)
m = \frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}
(x
2
−x
1
)
(y
2
−y
1
)
= \frac{4-0}{5-3}
5−3
4−0
= \frac{4}{1}
1
4
= 4 ]
3). The slope of the graph is equal to -1 for x between x = 5 and x = 9.
[Slope of the line passing through two points (5, 4) and (9, 0),
Slope = \frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}
(x
2
−x
1
)
(y
2
−y
1
)
= \frac{4-0}{5-9}
5−9
4−0
= -\frac{4}{4}
4
4
= -1 ]
4). The greatest value of y is y = 4, and it occurs when x = 5. (From the given graph)
