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bija089 [108]
3 years ago
11

Percents that are added together are _______ percents.

Mathematics
1 answer:
vivado [14]3 years ago
4 0
Percents that are added together are combining percents.
You might be interested in
1.
Fed [463]

Answer:

The out put 1. 5

The out put 2. 6

Step-by-step explanation:

What is this sopost to mean?

Srry if that did not helps much I tried my best

Please give me Brainliest

I really need it plz

3 0
3 years ago
Read 2 more answers
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
If someone could please explain to me how to do/work these out that would be great!
Ganezh [65]

Answer:

Place both coordinates for the first question on a graph and draw a line. The answer is the coordinate that falls on that line.

Step-by-step explanation:

7 0
3 years ago
Leave the answer as an improper fraction​
Ghella [55]

Hey there!

ANSWER: \frac{23}{20}

EXPLANATION:

To find the answer to your question, you will need to add.

\frac{3}{4}+\frac{2}{5}

First, multiply the denominator.

5*4=20

So the denominator will be 20.

Now move on to the numerator. Multiply 5 by 3.

5*3=15

Now multiply 4 bu 2.

4*2=8

If you want to get the numerator, add what you got after multiply.

15+8=23

The numerator is 23. So now let's complete the fraction.

\frac{23}{20}

This is your answer!

Hope this helps!

-TestedHyperr

3 0
3 years ago
Would you rather use color tiles or your ruler to measure the length of an object
Step2247 [10]
A ruler to measure the length of an object.
4 0
3 years ago
Read 2 more answers
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