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anyanavicka [17]
3 years ago
7

Evaluate ƒ(x) = 3x + 8 for x = 1.

Mathematics
2 answers:
sesenic [268]3 years ago
8 0
F equals 11 because it three times 1 plus eight.
navik [9.2K]3 years ago
5 0

Answer:  The required value of f(x) for x = 1 is 11.

Step-by-step explanation:  We are given to evaluate f(x) for x = 1, where

f(x)=3x+8~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To evaluate the required value, we need to substitute x = 1 in expression (i).

So, putting x = 1 in (i), we get

f(1)=3\times1+8=3+8=11.

Thus, the required value of f(x) for x = 1 is 11.

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Combine like terms to create an equivalent expression.<br> 3.26d+9.75d−2.65
statuscvo [17]

Answer:

13.01d-2.65

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s
ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3  and c = 36 inches.

  • Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\

  • Part B: Show how to use the unit circle to find tan A

Using the chart of unit circle, the value of tangent A can be found out. The tangent A is,

\tan A=\tan 30^o\\\tan A=\dfrac{1}{\sqrt{3}}

  • Part C: Calculate the area of ΔABC.

Use the following formula to find area of ΔABC.,

A=\dfrac{ab.\sin C}{2}\\A=\dfrac{18\times18\sqrt{3}.\sin C}{2}\\A=280.6\rm\; in^2

Thus, the measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

Learn more about the law of cosine here;

brainly.com/question/4372174

#SPJ1

7 0
2 years ago
Which of the following best describes the slope of the line below? pls help asap
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

Undefined.

3 0
2 years ago
Read 2 more answers
66
likoan [24]

Answer: 230cm²

Step-by-step explanation:

>We can do this by splitting the figure into 2 trapeziums.

>Additionally, you can see that both trapeziums bear the same lengths a and b. Hence, we can use this formula: \frac{1}{2} * (a+b) * (total height).

>Thus,

Area = \frac{1}{2} *(7+16)*20=230

4 0
2 years ago
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The area of a rectangle is 44 square units. Its length measures 4 units. Find the length of its diagonal. Round to the nearest t
NikAS [45]

Answer:

√(137)

Step-by-step explanation:

First, you will need to find the other side length.....then you can use the Pythagorean Theorem to find the diagonal:

L x W = 44

4 x W = 44

W =11

Now the Pythag, Theorem:

 diagonal^2 = 4^2 + 11^2

        d^2 = 16+121

         d^2 = 137

          d = √(137)

3 0
2 years ago
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