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Ulleksa [173]
3 years ago
9

Graph the function f(x) = x3 – 4x – 1. Which are approximate solutions for x when f(x) = 0?

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

x = 1, √5, -√5

Step-by-step explanation:

Graphing of Function:

The given function will cut the y-axis at (0,-1) and it will cut the x-axis at (0,1),(0,√5), (0.-√5).

We are given the function f(x) = x^3 - 4x - 1 = 0

We have to  approximate the solutions when f(x) = 0, that is,

f(x) = x^3 - 4x - 1 = 0 = 0

⇒ x^3 - 4x = 1

⇒ x(x^2 - 4) = 1

⇒ x = 1, x^2 - 4 = 1

Now, x^2 - 4 = 1

⇒ x^2 = 5

⇒ x = ±√5

Thus, x = 1, √5, -√5

Scilla [17]3 years ago
5 0
If f(x) is = to 0 then that means that you would have to plug the 0 in for all of the x that are in the function and the solve it.
f(x)= x3-4x-1
f(0)= (0)3-4(0)-1
0        0        0 -1
-1 
so that means that -1 would be the answer for the function
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I do not get this at all
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