Answer:
d is the right answer hope this helps
375 because 15 x 5 = 75 so 75 x 4 = 300 plus his 75. So all together the answer is 375. hope this helped.
In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.
P=(no. of favourable outcomes)/(no. of possible outcomes)
When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.
1) P(getting 1)=1/6
expected frequency of getting 1
=P(getting)1)×no. of trials
=1/6×600=100
But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.
Therefore, the dice is not fair.
2) P(getting a tail)=0.3
estimate for the number of times the coin will land on a tail
=expected frequency of getting a tail
=P(getting a tail)×no. of trials
=0.3×150=45
3)P(getting a six)=2/3
expected frequency of getting a six
=P(getting a six)×no. of trials
=2/3×300=200
4)P(getting a three)=0.5
expected frequency of getting a three
=P(getting a three)×350
=0.5×350=175
Step-by-step explanation:
Confidence interval = 90% = 0.90.
1 - 0.90 = 0.10
Mean of 15 batch:
724+718+776+760+745+759+795+756+742+740+761+749+739+747+742 = 11253/15
= 750.2
Mean of second batch:
735+775+729+755+783+760+738+780
= 6055/8
= 756.875
Sd = 20
Z-alpha/2 = 1.64
= (750.2-756.875)-1.64*√20²/15 + 20²/8
= -21.0348
(750.2-756.875)+1.64*√20²/15 + 20²/8
= 7.68
2. The upper limit of the interval is less than 10 so in conclusion the difference in mean batch viscosity is about 10 or less than 10