<span>
Exercise #1:
Point H = (–2, 2)
Point J = (–2, –3)
Point K = (3, –3)
It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points J and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.
Notice that point-J is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-J is one corner of the square.
H is another corner of the square. It's 5 units above J.
K is another corner of the square. It's 5 units to the right of J.
The fourth corner is (2, 3) ... 5 to the right of H,
and 5 above K.
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Exercise #2:
</span><span>Point H = (6, 2)
Point J = (–2, –4)
Point K = (-2, y) .
</span><span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
</span><span>Notice that points J and K have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
We need K to connect to point-H in such a way that it's on
the same horizontal line as H. Then the vertical and horizontal
lines that meet at K will be perpendicular, and we'll have the
right angle that we need there to make the right triangle.
So K and H need to have the same y-coordinate.
H is the point (6, 2). So K has to be up at (2, 2) .
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Exercise #3:
</span>
<span>Point H = (-6, 2)
Point J = (–6, –1)
Point K = (4, 2) .
</span>
<span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
This exercise is exactly the same as #1, except that it's a
rectangle instead of a square. It's still make of horizontal
and vertical lines, and that's all we need to know in order
to solve it.</span><span>
Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points H and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.
Notice that point-H is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-H is one corner of the rectangle.
J is another corner of the rectangle. It's 3 units below H.
K is another corner of the square. It's 4 units to the right of H.
The fourth corner is (2, -1) ... 4 to the right of J,
and 3 below K.
</span>
The plc as value of 6 in12.6 is the tenths place
Answer:
David made $18
Step-by-step explanation:
Leslie made $10. This means that you take 46-10=36
Chen-Chen made twice as much as David so 36/2=18 So Chen made $9.
David- 36-18= 18 So, David made 18 dollars.
Answer:
Step-by-step explanation:
It must be a trapezoid because a trapezoid has at least one set of parallel sides. Sides of equal length don't mean anything really unless we know hose sides are parallel. I will say sometimes I hear trapezoids ONLY have two parallel sides, while the other two are not, while in other places as long as two are parallel it is a trapezoid. It looks like for this question it is using the definition that at least two parallel sides makes it a trapezoid.
it can be an isosceles trapezoid since it is a type of trapezoid, same with right trapezoid. Basically any special kind of trapezoid
parallelogram because it can have two pairs of parallel lines and have thos parallel sides be equal. So this also means it can be all kinds of parallelograms.
Do you have a list to choose from? because most I pull up don't include right trapezoid at least.
This leaves kite as the only kind of quadrilateral to look at yet, and it specifies no parallel sides. bt your shape need at least one set of them, so it cannot be a kite.
Answer:
Part 15) The next three terms are 5/8,3/4 and 7/8
Part 16) The 37th term is -35.5
Step-by-step explanation:
we know that
In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)
Part 15) Find the next three terms of the arithmetic sequence
so
The common difference is equal to
d=1/8
<u><em>Find the next three terms of the arithmetic sequence</em></u>
<u><em>Find a5</em></u>
----->
<u><em>Find a6</em></u>
----->
<u><em>Find a7</em></u>
----->
therefore
The next three terms are
5/8,3/4 and 7/8
Part 16) what is the 37th term of the arithmetic sequence
so
The common difference is equal to
d=-1.1
We can write an Arithmetic Sequence as a rule
substitute the values
For n=37
substitute
