∫ e^(3x)*(cosh(2x)dx
= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx
= ∫ [(e^(5x)+e^x)/2]dx
=e^(5x)/10+e^x/2+C
=(1/10)(e^(5x)+5e^x)+C
Answer:
W=5
Step-by-step explanation:
40+4w=12w
-4w -4w
40= 8w
÷8 ÷8
5=w
The answer would be the first equation!!!!