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3 years ago

Evaluate ∫ e3x cosh 2x dx A. 1/2e5x + 1/2ex + C B. 1/10e5x + 1/5 x + C C. 1/10e5x + 1/2ex + C D. 1/4e3x + 1/2 x + C

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

6 0

∫ e^(3x)*(cosh(2x)dx

= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx

= ∫ [(e^(5x)+e^x)/2]dx

=e^(5x)/10+e^x/2+C

=(1/10)(e^(5x)+5e^x)+C

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