9a - ab + 5b<br><br>if a = 2 and b = 7

The data below represents the number of customers at each Slurpee Sam's Spaghetti Shop. 24, 25, 29, 30, 31, 31, 32, 34, 34. Whic

NeX [460]

Answer:

A summary of the data is as follows;

1. Maximum = 34

2. Minimum = 24

3. The 1st quartile is 27

4. The median is or the 2nd quartile 34

5. The 3rd quartile is 33

The data is summarized in the attached box plot

Step-by-step explanation:

24, 25, 29, 30, 31, 31, 32, 34, 34

From the given data, we have the five values of a box and whisker plot as follows;

1. Maximum = 34

2. Minimum = 24

3. The 1st quartile is the $\frac{9 + 1}{4} th$ term or 27

4. The median (2nd quartile) is the $\frac{9 + 1}{2} th$ term or 34

5. The 3rd quartile is the $\frac{3(9 + 1)}{4} th$ term or 33

Hence the attached box plot summarizes the data.

6 0

2 years ago

Determine the value of x (ill give brainliest)

Zina [86]

Answer:

I believe the answer is 7

4 0

2 years ago

Read 2 more answers

This is pre calculus please help !Describe three ways to determine the measure of segment YZ.

Dmitry [639]

(1) Using trigonometric ratios:
$sin(30) = \frac{YZ}{50}$
$YZ = 25$

(2) Using Pythagoras' Theorem:
$cos(30) = \frac{XY}{50}$
$50cos(30) = XY$
$50^{2} - 50^{2}cos^{2}(30) = YZ^{2}$
$2500 - 2500cos^{2}(30) = YZ^{2}$
$YZ = 25$

(3) Using sine rule:
$\frac{50}{sin(90)} = \frac{YZ}{sin(30)}$
$50 = \frac{YZ}{sin(30)}$
$50sin(30) = YZ$
$YZ = 25$

7 0

3 years ago

Read 2 more answers

Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .

anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

$tan (x) =\frac{sin(x)}{cos(x)}$

So we can replace into our formula and we got:

$tan(x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We have the following identities useful for this case:

$sin(a-b) = sin(a) cos(b) - sin(b) cos(a)$

$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$