x^2 - 2x = 146
x^2 - 2x - 146 = 0
See attachment. The quadratic formula is needed in this case.
Let
n-------> the number of nickels
q------> the number of quarters
we know that

so
----> equation A
----> equation B
substitute equation B in equation A
![0.05n+0.25[3n]=1.60](https://tex.z-dn.net/?f=0.05n%2B0.25%5B3n%5D%3D1.60)



Find the value of q

therefore
<u>The answer part a) is</u>
the number of nickels are
and the number of quarters are 
<u>the answer Part b) is</u>
The expressions that represents the number of quarters is
If you follow the order of pemdas the answer would be (-24)
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
15 units because I need to have