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3 years ago

There are many moons in the Solar System. Which statement best describes how moons typically move?

Chemistry

2 answers:

andriy [413]3 years ago

7 0

C each moon orbit a planet and also orbit the Sun

malfutka [58]3 years ago

6 0

Answer: The correct answer is Option C.

Explanation:

Solar system consists of a star, planets, moons, satellites of the planets, asteroids, meteoroids and comets.

Our solar system is named after the star which is Sun. Sun in roman means "Sol" and hence, the name solar system.

Our solar system consists of eight planets which revolve around the Sun and planets have moons which revolve around the planet. As, planets revolve around the Sun, therefore moons also revolve around the Sun.

Therefore, the correct answer is Option C.

You might be interested in

Calculate the concentration of OH-in a solution that has a concentration of H+ = 8.1 x 10^−6 M at 25°C. Multiply the answer you

Nat2105 [25]

Answer:

The answer is 12.35

Explanation:

From the question we are given that the concentration of $H^{+}$ is $8.1 * 18^{-6}M$

Generally The rate equation is given as

$K_{w} = [H^{+} ][OH^{-} ]$

and $K_{w}$ the rate constant has a value $1 * 10^{-14}$

Substituting and making [ $OH^{-}$ ] the subject we have

$[OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}$

$[OH ^ {-}] = 1.235 * 10^{-9}M$

Multiply the value by $10^{10}$ as instructed from the question we have

Answer = $1.235 * 10 ^{-9} * 10^{10} = 12.35$

Hence the answer in 2 decimal places is 12.35

7 0

4 years ago

What is the empirical formula of a compound with 35.94% aluminum and 64.06% sulfur

Sunny_sXe [5.5K]

Al S

1) 35.94 =1.33111 64.06 = 2.001875

27 32

2) = 1.33111 = 2.001875

1.33111 1.33111

3) = ( 1 ) × 2 = ( 1.5 ) ×2

4) = 2 = 3

Empirical Formula = Al2S3

1) Divide the percentage given in question by the Relative Atomic Mass (RAM)

of the given elements.

2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.

3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)

Hope this helps you :)))

Please give this a brainliest

6 0

3 years ago

When 18.0 mL of a 8.43×10-4 M cobalt(II) fluoride solution is combined with 22.0 mL of a 9.72×10-4 M sodium hydroxide solution d

Eva8 [605]

Answer:

Q = 1.08x10⁻¹⁰

Yes, precipitate is formed.

Explanation:

The reaction of CoF₂ with NaOH is:

CoF₂(aq) + 2 NaOH(aq) ⇄ Co(OH)₂(s) + 2 NaF(aq).

The solubility product of the precipitate produced, Co(OH)₂, is:

Co(OH)₂(s) ⇄ Co²⁺(aq) + 2OH⁻(aq)

And Ksp is:

Ksp = 3x10⁻¹⁶= [Co²⁺][OH⁻]²

Molar concentration of both ions is:

[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022)L = 3.79x10⁻⁴M

[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022)L = 5.35x10⁻⁴M

Reaction quotient under these concentrations is:

Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²

Q = 1.08x10⁻¹⁰

As Q > Ksp, the equilibrium will shift to the left producing Co(OH)₂(s) the precipitate

8 0

4 years ago

Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:

AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

Mass of Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

Mass of Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

5 0

3 years ago

Identify the element symbol 1s22s22p63s23p64s23d104p65s24d5

madam [21]

Answer:

Explanation:

You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!

5 0

1 year ago