5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Learn more: brainly.com/question/15288923
3–ethyl–2,4–dimethylhexane
CH₃-CH(CH₃)-CH(C₂H₅)-CH(CH₃)-CH₂-CH₃
Answer:
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Explanation:
Balanced chemical reaction:
C₃H₈(g) + 3H₂O(g) → 3CO(g) + 7H₂(g).
M(C₃H₈) = 44.1 g/mol; molar mass of propane.
M(H₂) = 2 g/mol; molar mass of hydrogen.
From balanced chemical reaction: n(C₃H₈) : n(H₂) = 1 : 7.
7m(C₃H₈) : M(C₃H₈) = m(H₂) : M(H₂).
7·8310 kg : 44.1 g/mol = m(H₂) : 2 g/mol.
m(H₂) = 2638.09 kg; mass of hydrogen.