Answer: 1/12
1/4 divided by 3/1
KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.
1/4* 31
1*1=1
4*3=12
1/12
Answer:
Explanation:
Hello,
In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:
That it terms of molarities and volumes we have:
Next, solving for the volume of lithium hydroxide we obtain:
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Answer:
Kc = 50.5
Explanation:
We determine the reaction:
H₂ + I₂ ⇄ 2HI
Initially we have 0.001 molesof H₂
and 0.002 moles of I₂
If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.
H₂ + I₂ ⇄ 2HI
In: 0.001 0.002 -
R: x x 2x
Eq: 0.001-x 0.002-x 0.00187
x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted
So in the equilibrium we have:
0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂
0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂
Expression for Kc is = (HI)² / (H₂) . (I₂)
0.00187 ² / 6.5×10⁻⁵ . 1.065×10⁻³ = 50.5
The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
<h3>What is the Grignard reagent?</h3>
The Grignard reagent is a compound that contains alkyl magnesium halide.
a) The student will be unsuccessful to prepare a Grignard reagent from 4-bromocyclohexanol because of the -OH group that reacts with the Grignard reagent when formed.
b) The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
c) The compound (2S, 3R)- 2,3-Dibromobutane has a specific rotation, [a]D, 0⁰ because it is a meso compound.
d) This is because, the tertiary alkyl halide is more prone to elimination reaction giving the alkene.
e) This is because, the reaction may be occurring by an SN1 mechanism and the rate determining step is the formation of the carbocation.
Learn more about substitution reaction:brainly.com/question/16811879
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