it takes 70 oz of grass seed to seed 2800ft of lawn. at this rate, how much would be needed for 3600 ft of lawn?

1 answer:

4 0

Find the multiplier to get from 2800ft to 3600ft. Multiply the weight of seed required for 2800ft by this multiplier for your answer.
3600/2800=9/7
70*9/7=90 oz

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