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Amiraneli [1.4K]
3 years ago
6

it takes 70 oz of grass seed to seed 2800ft of lawn. at this rate, how much would be needed for 3600 ft of lawn?

Mathematics
1 answer:
Rom4ik [11]3 years ago
4 0
Find the multiplier to get from 2800ft to 3600ft. Multiply the weight of seed required for 2800ft by this multiplier for your answer.
3600/2800=9/7
70*9/7=90 oz
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What is the value of x?
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Answer:

<h2>x = 3</h2>

Step-by-step explanation:

Look at the picture.

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\dfrac{4}{3}=\dfrac{x}{2.25}            <em>cross multiply</em>

3x=(4)(2.25)

3x=9             <em>divide both sides by 3</em>

x=3

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3 years ago
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Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.
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Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

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4 years ago
The elevation at ground level is 0 feet. An elevator starts 90 feet below ground level. After traveling for 15 seconds, the elev
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7 0
3 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

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2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

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∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
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