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Elena-2011 [213]
3 years ago
13

How to find the least value of quadratic expression 5-(x+3)^2

Mathematics
1 answer:
Mariana [72]3 years ago
5 0
Least value  is negative infinity
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Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2
MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

The given line has a slope m1=5, thus the slope of our required line is:

\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}

The equation of the line now can be expressed as:

\displaystyle y=-\frac{1}{5}x+b

We need to find the value of b, which can be done by using the point (7,2):

\displaystyle 2=-\frac{1}{5}*7+b

Operating:

\displaystyle 2=-\frac{7}{5}+b

Multiplying by 5:

10=-7+5b

Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

7 0
3 years ago
Ihorangi travels 51 km to work and 51 km from work each day.
viktelen [127]

Answer:

Ihorangi uses 7.65 litres of petrol to and from work

Step-by-step explanation:

If the car Ihorangi drives consumes 7.5 L/100 km

Then for 1 km journey, the car will consume 7.5/100 L

= 0.075 L

If Ihorangi travels 51 km to work and 51 km from work

Therefore Ihorangi travel (51 + 51) km daily to and from work

= 102 km daily

The fuel he consumes daily is 102*0.075 L

= 7.65 L

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The answer is 1.1 x10^7
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Ralph's height is y
Ben's height is x

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There is a book sale at the libaray the price for each book is $4 which expression can be used to show how much money the librar
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4 x 289= the total cost
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