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Viefleur [7K]
3 years ago
6

If the measure of one angle in a supplementary pair is double the other angle,find the measure of larger angle.

Mathematics
1 answer:
defon3 years ago
4 0
In a parallelogram sum of the adjacent angles

equals supplementary.

opposite angles are equal.

Let the smaller angle = x°

larger angle = twice the smaller angle - 30°

=2x° - 30°

x° +2 x° - 30 = 180°

3x° = 180 + 30

3x = 210

x = 210 / 3

x = 70°

Therefore,

smaller angle = x = 70°

larger angle = 2x - 30

= 2 × 70 - 30

= 140 - 30

= 110°

Required parallelogram angles are 70° , 110° ,

70° , 110°

I hope this helps you.

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Any number is divisible by 2 is also divisible by 6 find a counter example to show that conjecture is false
likoan [24]

Answer:

  2

Step-by-step explanation:

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5 0
3 years ago
A tree is 6 feet 7 inches tall. How tall is it in inches?
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79 inches

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6 0
2 years ago
Find the point on the line 2x+4y−3=0 which is closest to the point (2,0)
Finger [1]
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P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P. 

Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2)  =>
L2: 2x-y-4=0.............(2)

Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
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x=19/10

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7 0
3 years ago
Help please!!
Free_Kalibri [48]
Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0

tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0

tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0

tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0

( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0


tan( θ ) - 1 = 0

θ = π/₄

tan( θ ) - √3 = 0


θ = π/₃


so θ = π/₄ and θ = π/₃
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