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igor_vitrenko [27]
3 years ago
9

The product of two consecutive negative even integers is 24. What is the smaller of the two numbers?

Mathematics
2 answers:
nignag [31]3 years ago
5 0

Answer:

A. -6

Step-by-step explanation:

Karo-lina-s [1.5K]3 years ago
3 0

Answer:

The smaller one is -6, the bigger one is -4.

Step-by-step explanation:

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Hosea's doctor has recommended that his daily diet should include 5 vegetables, 5 fruits, and 4 whole grains. At the grocery sto
Scilla [17]

Answer:

100

Step-by-step explanation:

Given that Hosea's doctor has recommended that his daily diet should include 5 vegetables, 5 fruits, and 4 whole grains.

At the grocery store, Hosea has a choice of 19 vegetables, 7 fruits, and 9 whole grains.

Since he does not like to eat 2 servings of the same thing in 1 day the choices of vegetables, fruits and grains should be without repitition.

so combination can be used

No of ways  can he get his daily requirements if he doesn't like to eat 2 servings of the same thing in 1 day

= 5C1*5C1*4C1\\= 100

3 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!! I GIVE BRAINLIAST <3)))
Goryan [66]

8. domain=hours

range=cost

it is a function because there is a y value for ever x

9. minutes =60, 120,180, 240 (domain)

calories= 360, 720, 1080, 1440 (range)

this is also a function

6 0
3 years ago
In 2000 the population of a country reached 1 ​billion, and in 2025 it is projected to be 1.2 billion. ​(a) Find values for C an
Mice21 [21]

Answer:

(a) The value of C is 1.

(b) In 2010, the population would be 1.07555 billions.

(c) In 2047, the population would be 1.4 billions.

Step-by-step explanation:

(a) Here, the given function that shows the population(in billions) of the country in year x,

P(x)=Ca^{x-2000}

So, the population in 2000,

P(2000)=Ca^{2000-2000}

=Ca^{0}

=C

According to the question,

P(2000)=1

\implies C=1

(b) Similarly,

The population in 2025,

P(2025)=Ca^{2025-2000}

=Ca^{25}

=a^{25}                    (∵ C = 1)

Again according to the question,

P(2025)=1.2

a^{25}=1.2

Taking ln both sides,

\ln a^{25}=\ln 1.2

25\ln a = \ln 1.2

\ln a = \frac{\ln 1.2}{25}\approx 0.00729

a=e^{0.00729}=1.00731

Thus, the function that shows the population in year x,

P(x)=(1.00731)^{x-2000}     ...... (1)

The population in 2010,

P(2010)=(1.00731)^{2010-2000}=(1.00731)^{10}=1.07555          

Hence, the population in 2010 would be 1.07555 billions.

(c) If population P(x) = 1.4 billion,

Then, from equation (1),

1.4=(1.00731)^{x-2000}

\ln 1.4=(x-2000)\ln 1.00731

0.33647 = (x-2000)0.00728

0.33647 = 0.00728x-14.56682

0.33647 + 14.56682 = 0.00728x

14.90329 = 0.00728x

\implies x=\frac{14.90329}{0.00728}\approx 2047

Therefore, the country's population might reach 1.4 billion in 2047.

3 0
3 years ago
Mark all true statements. Group of answer choices
laiz [17]

Answer:

True

False

Step-by-step explanation:

a) The first statement is the basis for Euclid's algorithm to compute the gcd of two nonnegative integers a,b. You can prove this as follows.

Let G=gcd(a,b). Since r=a-bq and G divides a and G divides b, then G divides r. Now, G divides a and G divides r, hence G divides gcd(b,r).

On the other hand, since a=bq+r, and gcd(b,r) divides b and r, then gcd(b,r) divides a. Therefore gcd(b,r) divides a and b, which implies that gcd(b,r) divides G.

x divides y and y divides x implies that |x|=|y|. The GCD's are nonnegative, therefore G=gcd(b,r).

b) It is false. In general, to test for primality of N, you have to check that all primes smaller than N do not divide N. In this case, we have to check for 2,3,5,7,11,13,17,19,23,...

101 is prime, but this may be false in general. For example, consider N=13*11=143. N is not prime, and n is not divisible by 2,3,5, or 7.

5 0
3 years ago
PLEASE HELP!! i cant figure out how to do it
vodomira [7]

Answer:

168 and 12

Step-by-step explanation:

use fractions for this think of it as 14/15x and 1/15x and x is 180 and solve from there

3 0
2 years ago
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