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NNADVOKAT [17]
2 years ago
5

State whether the data described below are discrete or continuous, and explain why. The weights of dogs (in pounds) at a dog sho

w
A. The data are discrete because the data can take on any value in an interval.
B. The data are discrete because the data can only take on specific values.
C. The data are continuous because the data can only take on specific values.
D. The data are continuous because the data can take on any value in an interval.
Mathematics
1 answer:
Stels [109]2 years ago
5 0

Answer: D. The data are continuous because the data can take on any value in an interval.

Step-by-step explanation: When distinguishing between quantitative variables, they could be classed as either discreet or continuous. This difference between a discreet and continuous variable lies in whether the variable has a finite number of values or not. When a variable can only take up a certain number of values usually while numbers within a certain interval, then such varibak eis said to be finite. On the other hand variables which can take up any value within an interval are said to be continuous as they can take up an uncountable number of values within an interval. When weight is being recorded, it could take up an infinite number of values including decimal within an interval making it difficult to ascertain the number of possible values within the interval.

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Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u><u> </u><u>and</u><u> </u><u>c</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

Step-by-step explanation:

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{ \rm{y = mx + c}}

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[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

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{ \rm{3y =  - 3 - 6x}} \\  \\ { \rm{3y =  - 6x - 3}} \\  \\ { \rm{ \frac{3y}{3}  =  \frac{ - 6x}{3}  -  \frac{3}{3} }} \\  \\  { \boxed{ \rm{y =  - 2x - 1}}}

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{ \rm{m \:  \dashrightarrow \:  - 2}} \\  \\ { \rm{c \:  \dashrightarrow \:  - 1}}

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