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AnnyKZ [126]
3 years ago
11

What is 2/9 + 2/3 and simplify if can

Mathematics
2 answers:
ratelena [41]3 years ago
7 0

2/9 + 2/3

2*3=6

3*3=9

2/9 + 6/9 = 8/9

vova2212 [387]3 years ago
4 0

2/9+2/3=2/9+6/9=8/9

8/9

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a gardenner is designing a new garden in the shape of a trapezoing she wants the short base to be twice the height and loger bas
taurus [48]

Answer:

Height = 5 ft

Short base = 10 ft

Long base = 14 ft

Step-by-step explanation:

Let h = height, a = short base, b = long base.

From the question,

a = 2h

b = a + 4 = 2h + 4

The area of the trapezoid is given by \frac{1}{2}(a+b)h. Thus,

60 = \frac{1}{2}(2h + 2h + 4)h

60 = \frac{(4h  + 4)h }{2}

60 = \frac{4h(h  + 1)}{2}

60 = 2h(h  + 1)

30 = h(h  + 1)

0 = h^2  + h - 30

0 = (h+6)(h-5)

h-5 = 0 or h+6 = 0

h= 5 or h = -6

We discard the negative value of h since it is a measurement and cannot be negative.

h= 5

a= 2h=2\times5=10

b= a+4=10+4=14

6 0
3 years ago
The perimeter of a square JKLM is 48 units ..what is the x?
erastova [34]
P=4*a, where P - perimeter, a - length of one side of the square.
if a=x+3 and P=48, then 4(x+3)=48;
x=9.
Answer: 9 units.
4 0
3 years ago
Read 2 more answers
If A, B, and C are collinear, and AB = 18, AC = 41, what is a possible measure of BC?
ikadub [295]

Step-by-step explanation:

As ANC are collinear,

AB+BC=AC

so,

18+BC = 41

BC = 41-18

BC = 23 is the answer.

8 0
3 years ago
Read 2 more answers
The height of a football is given by the function h of t equals negative16 t squared plus 56 t plus 3, where h of t is the heigh
kykrilka [37]

Answer:

27 feet.

Step-by-step explanation:

Graph the quadratic equation, then find the point on the graph which aligns with x=3. Y would equal 27.

8 0
2 years ago
2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1​
Misha Larkins [42]

\\ \sf\longmapsto L-M

  • Put values

\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]

Just substract corresponding terms

\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]

Option B

6 0
2 years ago
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