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bearhunter [10]
3 years ago
7

Two real solutions of tx^2+3x_7=0

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

/Delta=b^2-4ac

If /Delta>0 there are two distinct solutions

If /Delta=0 there are two coincident solutions

If /Delta<0 there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

The number of solutions of a quadratic equation

Depends on its discriminant

If there are two distinct solutions

If there are two coincident solutions

If there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]

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uysha [10]
B 9x+10, this is because you just simply combine like terms
5 0
3 years ago
A function has y-intercept of -2 and a slope of -3/5. Which equation below describes the function?
alexandr402 [8]

D.y = -3/5x - 2

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6 0
3 years ago
Fill in the missing number in this newspaper report:
natka813 [3]

Answer:

£125000

Step-by-step explanation:

Original cost of house = £100 000

Percent increase = 25%

Increase in price = 25% of 100,000

Increase in price = 0.25 * 100,000

Increase in price = 25000

New cost = original cost + Increment

New cost = 100,000 + 25,000

New cost = 125,000

Hence it now cost  £125000

8 0
2 years ago
Find the exact value of T Image below
Elanso [62]

Answer:

a) 1/800 or 0.00125

b) i) 0.0013

ii) 0.001

c) 60%

Step-by-step explanation:

T = [tan(2×30)+1][2cos(30)-1] ÷ (y²-x²)

T = (tan60 + 1)(2cos30 - 1) ÷ (41² - 9²)

T = (sqrt(3) + 1)(sqrt(3) - 1) ÷ 1600

T = (3-1)/1600

T = 2/1600

T = 1/800

T = 0.00125

Error: 0.002 - 0.00125

0.00075

%error

0.00075/0.00125 × 100

60%

4 0
3 years ago
Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/
ArbitrLikvidat [17]
G `( x ) =2x * e^{kx}  + k x^{2} *e^{kx} = \\  = xe^{kx}(2 + kx )
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3. 
8 0
3 years ago
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