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bearhunter [10]
3 years ago
7

Two real solutions of tx^2+3x_7=0

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

/Delta=b^2-4ac

If /Delta>0 there are two distinct solutions

If /Delta=0 there are two coincident solutions

If /Delta<0 there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

The number of solutions of a quadratic equation

Depends on its discriminant

If there are two distinct solutions

If there are two coincident solutions

If there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]

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The perimeter of a circle, often called the circumference, is proportional to its diameter and its radius.

Step-by-step explanation:

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Why is the initial value and y-intercept the same thing on a graph?? someone please explain
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Anna earns $48 for washing cars for 6 hours. If Anna charges at the same rate, how many hours will it take her to earn $72?
Ivanshal [37]

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3 years ago
What is the length of segment AC?
Andrei [34K]

Answer:

10 units

Step-by-step explanation:

To find the length we can use the formula

d = sqrt( (y2-y1)^2 + (x2-x1)^2)

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d = sqrt( (-1-5)^2 + (3--5)^2)

d = sqrt( (-6)^2 + (3+5)^2)

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4 0
3 years ago
Find the midpoint of the segment with the given endpoints.<br> (-10,- 6) and (-3,7)
Marina CMI [18]

Step-by-step explanation:

in essence, these 2 points are the Hypotenuse of a right-angled triangle. the legs are the coordinate differences between the 2 points creating the 3rd point of that triangle at (-10, 7) : the x coordinate of one point, and the y coordinate of the other.

now, we are looking for the midpoint. this midpoint cuts the original line/hypotenuse in half creating a scaling factor of 1/2.

when we create now a similar triangle based on that "half- Hypotenuse", we need to use the same scaling factor also on the legs (the coordinate differences).

so, when we cut the coordinate differences also in half, we get the coordinates for the midpoint on the main line.

xm, ym are the coordinates of the midpoint.

xm = (x1 + x2)/2 = (-10-3)/2 = -13/2 = -6.5

ym = (y1 + y2)/2 = (-6+7)/2 = 1/2 = 0.5

so, the midpoint is (-6.5, 0.5)

8 0
2 years ago
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