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zysi [14]
3 years ago
8

Given the data presented in the bar graph, which fruit represents 10% of the fruit for the people surveyed? A) Apple B) Banana C

) Kiwifruit D) Orange

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

It must be B banana because it is the smallest compared to the other ones

Ann [662]3 years ago
4 0

Answer: B) Banana

Step-by-step explanation:

Add the amount of people who voted for each fruit to get the total amount of people. 35+30+15+25+40+5 = 150.

Now, just find 10% of 150 by multiplying 150 by .10

10% of 150 is 15, 15 people that were surveyed chose banana. :)

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What is the difference between discrete vs continuous data
Sergeeva-Olga [200]
With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)

On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4). 

-------------------------------------

With that in mind, we have the following answers

1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint

2) Continuous data. Like time values, temperatures can be averaged as well. 

3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.

4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds. 

5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
4 0
3 years ago
you better container of cat litter for 13.75 and a bag of cat food for x amount of dollars the total purchase is $20.80 which in
fenix001 [56]

I think its $6.22 for cat food

7 0
3 years ago
Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
3 years ago
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Step-by-step explanation:

Area of circle =πr²

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<h2>stay safe healthy and happy.</h2>
5 0
2 years ago
Read 2 more answers
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LekaFEV [45]

Answer:

£116.67

Step-by-step explanation:

Given;

Nar donated to 4 charities last year. She gave £175 to each of these charities.

The total amount Nar donated is;

Nar = 4 × £175 = £700

For Rana to donate the same amount equally among 6 charity, to determine the amount each charity would receive this year, we need to divide the total amount by the number of charities;

A = £700/6

A = £116.67

7 0
3 years ago
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