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3 years ago

The difference of three times a number and five is four. Find the number

Mathematics

1 answer:

givi [52]3 years ago

4 0

The difference of three times a number and five is four. Then the number is 3

<u>Solution:</u>

Given that,

Difference of three times a number and five is four

We have to find the number

Let us frame a equation using the given information and solve the sum

Let the number be "n"

Difference of three times a number and five = 4

Three times n - 5 = 4

3n - 5 = 4

3n = 9

On dividing 9 by 3 we get 3

n = 3

Thus the required number is 3

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Write a<br> as a repeating decimal.<br> Write 2/5 as a repeating decimal.

Svet_ta [14]

Answer:

0.4

Step-by-step explanation:

2/5 = 4/10

4/10 = 0.4

2/5 is not a repeating decimal.

Hope This Helps :)

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4%28a%20%2B%202%20%29%20-%202%20%28a%20-%203%29" id="TexFormula1" title="4(a + 2 ) - 2 (a - 3)

satela [25.4K]

Answer:

$\large\boxed{2a+14}$

Step-by-step explanation:

$4(a + 2 ) - 2 (a - 3)\qquad\text{use distributive property:}\ a(b+c)=ab+ac\\\\=4a+8-2a-(-6)\qquad\text{combine like terms}\\\\=(4a-2a)+(8+6)\\\\=2a+14$

5 0

3 years ago

Nate made 8 loaves of bread on Monday and 10 more on Tuesday. He gave an equal number to each of his 9 neighbors. How many loave

mars1129 [50]

Answer:

Step-by-step explanation:

8 + 10 = 18

18/9 = 2

8 0

3 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago

Someone pls help me

Nat2105 [25]

The answer should be AC+BC

We can answer this by applying the rule called "Greater angle, greater side". This is where in any triangle, the opposite side of the larger angle is also longer.

So in this question, first we have to find the largest 2 angles, which is ∠ABC and ∠BAC with measures of 120° and 35° respectively. Therefore, from the diagram, the opposite sides of the angles are AC and BC.

Therefore, the answer should be AC+BC.

7 0

3 years ago