Question

PLEASE HELP ASAP!!!!!!

Answer 1

Answer:- The value of x must be 6

Given:- ΔFGH and ΔKJH are congruent by SSS postulate such that GH=JH

and Point H is the midpoint of side FK.

⇒ FH=HK

As ΔFGH and ΔKJH

⇒ GF=JK  [congruence parts of two congruent triangles are equal]

⇒3x-2=2x+4

⇒3x-2x=4+2    [Add 2 and subtract 2x on the sides]

⇒x=6

Thus the value of x=6.

Answer 2

the answer would be x=6

to find it you would set 3x-2 equal to 2x+4 and solve because the two sides would be equal if the triangles are congruent

hope this helps :)