Answer:
C 1
Step-by-step explanation:
x-1/x-2 - x^2+4x-4/(x-2)(x+6)
rewrite: (x-1)(x+6)-(x^2 + 4x - 4)/(x-2)(x+6)
expand x^2+6x-x-6-x^2-4x+4/(x-2)(x+6)
collect like terms (x^2-x^2)+(6x-x-4x)+(-6+4)/(x-2)(x+6)
simplify x-2/(x-2)(x+6)
cancel x-2 and get 1/x+6
but that is the only answer I can get from this, so I believe many one, just because of the numerator
Answer:
The very first one is 22
Step-by-step explanation:
Answer:
a) 5units
b) (4.5, 4)
Step-by-step explanation:
Let the coordinate of P and Q be P(3, 2) and Q(6, 6)
PQ can be gotten using the distance formula;
PQ =√(6-2)²+(6-3)²
PQ = √4²+3²
PQ =√16+9
PQ =√25
PQ = 5units
Midpoint M is expressed as;
M(X, Y) = {(x1+x2)/2, y1+y2/2}
X = x1+x2/2
X = 3+6/2
X= 9/2
X = 4.5
Similarly;
Y = y1+y2/2
Y = 2+6/2
Y = 8/2
Y = 4
Hence the midpoint of PQ is (4.5, 4)
Answer:
Step-by-step explanation:
Remark
The problem asks you to identify the triangles. They are similar. The reason they are similar is by AA. That means that 2 of the angles are identified as equal in each triangle.
Proof
Both triangles contain a right angle....................That's given.
The mirror has an interesting property. It is stated as the angle of incidence = the angle of reflection. That property is marked by the lines hitting the mirror towards your right. If you do not know what incidence and reflection mean, just notice that the angles are marked as equal and call it given.
The base angles are equal ....................................Given
Here it is more formally
B and D are right angles ..................... Given
<AMB = <CMD Property of a mirror
Triangle AMB similar Triangle CMD AA in 1 triangle = AA in the other.
Answer:
Simulation --> An imitation
Sample --> The part of a population
Biased sample --> A sample that is not
Population --> A group
