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polet [3.4K]
3 years ago
15

When Liz woke up in the morning, it was 6°F. By the late afternoon, the temperature had dropped 9°F.

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

-3°F

Step-by-step explanation:

6 - 9 =  -3°F

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How many dimensions are in a point? <br><br> A. 0<br> B. 1<br> C. 2<br> D. 3
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0 dimensions are in a point

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Find the slope between (3,-1) and (-5,4)
vampirchik [111]
-5/8
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Find the 61st term of -12, -28, -44,
Citrus2011 [14]

Answer:

a_{61}=-972

Step-by-step explanation:

<u>Arithmetic Sequences</u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the first terms of a sequence:

-12, -28, -44,...

Find the common difference by subtracting consecutive terms:

r = -28 - (-12) = -16

r = -44 - (-28) = -16

The first term is a1 = -12. Now we calculate the term n=61:

a_{61}=-12+(61-1)(-16)

a_{61}=-12-60*16=-12-960

\mathbf{a_{61}=-972}

6 0
3 years ago
Mr. Clark claims that he has a coin that is weighted so that the probability of heads is 40%. To test this, his students flip th
mrs_skeptik [129]

Answer:

1. The relative frequency of heads is (A) reasonably close to 40%.

2. Mr. Clark's claim about the theoretical probability is likely to be (A) True.

3. This means that the theoretical probability of tails is most likely 0.6 for this coin.

( I also had this question before)

8 0
2 years ago
Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours. Then pumps Y and Z started working an
madam [21]

Answer:

The correct option is B) 12.

Step-by-step explanation:

Consider the provided information.

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours.

As we know: rate =\dfrac{ work}{time},

The rate of pump X is \frac{\frac{1}{4}}{2} = \frac{1}{8}

\frac{1}{4} of the water is pumped out of the tank, that means only \frac{3}{4} is left to be pumped out.  

All 3 pumps pumped out the remaining \frac{3}{4} of the water out in 3 hours.

The combined rate of all three pumps is: \frac{\frac{3}{4}}{3} = \frac{1}{4}

Pump Y, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water.

The rate of pump Y = \frac{\frac{3}{4}}{18} = \frac{1}{24}

Let z is the time taken by pump Z, then the rate of pump Z is \frac{1}{z}.

Therefore,

\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{z}=\dfrac{1}{4}

Multiplying both sides by 24 z.

3z + z + 24 = 6z\\24 = 2z\\12 = z

Hence, the correct option is B) 12.

5 0
3 years ago
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