I hope this helps you
3ax= c-b
x= c-b/3a
Answer:
-6
and there you have it plain and simple
Answer:
OK SO THE TABLE IS
6-152
7-160
8-147
SO I AM GUESSING THAT THE 6 STANDS FOR 6TH GRADE IF I AM WRONG LET ME KNOW KK
OK SO YOU WILL 3/4 DIVIDED BY 152 AND YOU WILL GET 114
ANSWER=114
WELL HOPE THIS HELPS LET ME KNOW IF THERE IS ANYTHING ELSE
1. You should draw a diagram with the information given in the problem. As you can see in the figure attached, there are two triangles, so, you can calculate the height of the lamp post as below:
h1/b1=h2/b2
h1 is the height asked.
b1=360 cm+ 90 cm
b1=450 cm
h2=160 cm
b2=90 cm
2. When you substitute these values into h1/b1=h2/b2, you obtain:
h1/450 cm=160 cm/90 cm
3. Now, you must clear the height "h1". Then, you have:
h1=(160 cm)(450 cm)/90 cm
h1=72000 cm²/90 cm
h1=800 cm
<span>
How high is the lamp post?
</span>
The answer is: 800 cm
Answer:
19.5°
Step-by-step explanation:
IN EFG the measure of G=90 DG=21 feet and EF=63 feet find the measure of E to the nearest degree.
We solve the question using Sine rule
= a/sin A = b/sin B
= 21/sin E = 63/sin 90
Cross Multiply
Sin E × 63 = 21 × sin 90
sin E = 21 × sin 90/63
E = arc sin( 21 × sin 90/63)
E = 19.47122°
Approximately = 19.5°