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3241004551 [841]
3 years ago
11

Plz help me find it

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

360 - 285 = 75

It would be 75.

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

leonid [27]3 years ago
4 0
360-285
=75
The answer is 75
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The slope of the line containing the points (-2,3) and (-3,1) is
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To calculate the slope containing two points, we can use that formula:


\mathsf{m=\dfrac{y_2-y_1}{x_2-x_1}}


"m" represents the slope and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


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2 years ago
What is the value of x in the equation 5(2x - 7) = 15x -10
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3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

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Substitute the values in the above equation, and we get

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simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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