1/2r -3= 3 (4-3/2r) is to be solved for r.
I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.
Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .
Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:
r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r
Now expand the right side, using the distributive property of
r - 3 = 24 - 9r
Regrouping so as to combine like terms:
10r = 30
Solving for r: r = 30/10 = 3
The value of r that satisfies this equation is 3
Answer:
3/28
Step-by-step explanation:
that dot is a multiplication sign, right?
Hello there, have a nice day
P=x+38
add all individual sides together (is also the perimeter):
p=(x+3)+(x-5)+x+(x-2)+(x-4)+(x-1)+(x-1)
=7x-10
set both p equal:
x+38=7x-10
38=6x-10
48=6x
8=x
then insert x=8 in all the side/perimeter equations:
p=x+38=8+38=46
sides:
x=8
x-2=8-2=6
x-1=8-1=7
x-4=8-4=4
x-5=8-5=3
x+3=8+3=11
Answer:
D: The function has a hole when x = 3, and vertical asymptotes when x = 0 and x = 5.
Step-by-step explanation:
The given rational function has vertical asymptotes and holes. Remember that an asymptote is placed when the function has undetermined results, when we give a x-value and the y-value cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.
So, in this case we have to undetermined results when the function has a hole of x = 3, and vertical asymptotes when x = 0 and x = 5.